Optimal. Leaf size=277 \[ -\frac{3}{4} \text{PolyLog}\left (4,\frac{2}{a x+1}-1\right )-\frac{3}{2} \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )-\frac{3}{2} \tanh ^{-1}(a x) \text{PolyLog}\left (3,\frac{2}{a x+1}-1\right )-\frac{141 a x}{256 \left (1-a^2 x^2\right )}-\frac{3 a x}{128 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}-\frac{33 a x \tanh ^{-1}(a x)^2}{32 \left (1-a^2 x^2\right )}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}+\frac{33 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )}+\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}+\frac{1}{4} \tanh ^{-1}(a x)^4-\frac{11}{32} \tanh ^{-1}(a x)^3-\frac{141}{256} \tanh ^{-1}(a x)+\log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)^3 \]
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Rubi [A] time = 0.626081, antiderivative size = 277, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 12, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.546, Rules used = {6030, 5988, 5932, 5948, 6056, 6060, 6610, 5994, 5956, 199, 206, 5964} \[ -\frac{3}{4} \text{PolyLog}\left (4,\frac{2}{a x+1}-1\right )-\frac{3}{2} \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )-\frac{3}{2} \tanh ^{-1}(a x) \text{PolyLog}\left (3,\frac{2}{a x+1}-1\right )-\frac{141 a x}{256 \left (1-a^2 x^2\right )}-\frac{3 a x}{128 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}-\frac{33 a x \tanh ^{-1}(a x)^2}{32 \left (1-a^2 x^2\right )}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}+\frac{33 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )}+\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}+\frac{1}{4} \tanh ^{-1}(a x)^4-\frac{11}{32} \tanh ^{-1}(a x)^3-\frac{141}{256} \tanh ^{-1}(a x)+\log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)^3 \]
Antiderivative was successfully verified.
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Rule 6030
Rule 5988
Rule 5932
Rule 5948
Rule 6056
Rule 6060
Rule 6610
Rule 5994
Rule 5956
Rule 199
Rule 206
Rule 5964
Rubi steps
\begin{align*} \int \frac{\tanh ^{-1}(a x)^3}{x \left (1-a^2 x^2\right )^3} \, dx &=a^2 \int \frac{x \tanh ^{-1}(a x)^3}{\left (1-a^2 x^2\right )^3} \, dx+\int \frac{\tanh ^{-1}(a x)^3}{x \left (1-a^2 x^2\right )^2} \, dx\\ &=\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}-\frac{1}{4} (3 a) \int \frac{\tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^3} \, dx+a^2 \int \frac{x \tanh ^{-1}(a x)^3}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac{\tanh ^{-1}(a x)^3}{x \left (1-a^2 x^2\right )} \, dx\\ &=\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{1}{4} \tanh ^{-1}(a x)^4-\frac{1}{32} (3 a) \int \frac{1}{\left (1-a^2 x^2\right )^3} \, dx-\frac{1}{16} (9 a) \int \frac{\tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^2} \, dx-\frac{1}{2} (3 a) \int \frac{\tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac{\tanh ^{-1}(a x)^3}{x (1+a x)} \, dx\\ &=-\frac{3 a x}{128 \left (1-a^2 x^2\right )^2}+\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}-\frac{33 a x \tanh ^{-1}(a x)^2}{32 \left (1-a^2 x^2\right )}-\frac{11}{32} \tanh ^{-1}(a x)^3+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{1}{4} \tanh ^{-1}(a x)^4+\tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )-\frac{1}{128} (9 a) \int \frac{1}{\left (1-a^2 x^2\right )^2} \, dx-(3 a) \int \frac{\tanh ^{-1}(a x)^2 \log \left (2-\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx+\frac{1}{16} \left (9 a^2\right ) \int \frac{x \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx+\frac{1}{2} \left (3 a^2\right ) \int \frac{x \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx\\ &=-\frac{3 a x}{128 \left (1-a^2 x^2\right )^2}-\frac{9 a x}{256 \left (1-a^2 x^2\right )}+\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}+\frac{33 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}-\frac{33 a x \tanh ^{-1}(a x)^2}{32 \left (1-a^2 x^2\right )}-\frac{11}{32} \tanh ^{-1}(a x)^3+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{1}{4} \tanh ^{-1}(a x)^4+\tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )-\frac{3}{2} \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )-\frac{1}{256} (9 a) \int \frac{1}{1-a^2 x^2} \, dx-\frac{1}{32} (9 a) \int \frac{1}{\left (1-a^2 x^2\right )^2} \, dx-\frac{1}{4} (3 a) \int \frac{1}{\left (1-a^2 x^2\right )^2} \, dx+(3 a) \int \frac{\tanh ^{-1}(a x) \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac{3 a x}{128 \left (1-a^2 x^2\right )^2}-\frac{141 a x}{256 \left (1-a^2 x^2\right )}-\frac{9}{256} \tanh ^{-1}(a x)+\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}+\frac{33 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}-\frac{33 a x \tanh ^{-1}(a x)^2}{32 \left (1-a^2 x^2\right )}-\frac{11}{32} \tanh ^{-1}(a x)^3+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{1}{4} \tanh ^{-1}(a x)^4+\tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )-\frac{3}{2} \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )-\frac{3}{2} \tanh ^{-1}(a x) \text{Li}_3\left (-1+\frac{2}{1+a x}\right )-\frac{1}{64} (9 a) \int \frac{1}{1-a^2 x^2} \, dx-\frac{1}{8} (3 a) \int \frac{1}{1-a^2 x^2} \, dx+\frac{1}{2} (3 a) \int \frac{\text{Li}_3\left (-1+\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac{3 a x}{128 \left (1-a^2 x^2\right )^2}-\frac{141 a x}{256 \left (1-a^2 x^2\right )}-\frac{141}{256} \tanh ^{-1}(a x)+\frac{3 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )^2}+\frac{33 \tanh ^{-1}(a x)}{32 \left (1-a^2 x^2\right )}-\frac{3 a x \tanh ^{-1}(a x)^2}{16 \left (1-a^2 x^2\right )^2}-\frac{33 a x \tanh ^{-1}(a x)^2}{32 \left (1-a^2 x^2\right )}-\frac{11}{32} \tanh ^{-1}(a x)^3+\frac{\tanh ^{-1}(a x)^3}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac{1}{4} \tanh ^{-1}(a x)^4+\tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )-\frac{3}{2} \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )-\frac{3}{2} \tanh ^{-1}(a x) \text{Li}_3\left (-1+\frac{2}{1+a x}\right )-\frac{3}{4} \text{Li}_4\left (-1+\frac{2}{1+a x}\right )\\ \end{align*}
Mathematica [A] time = 0.28276, size = 189, normalized size = 0.68 \[ \frac{1536 \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,e^{2 \tanh ^{-1}(a x)}\right )-1536 \tanh ^{-1}(a x) \text{PolyLog}\left (3,e^{2 \tanh ^{-1}(a x)}\right )+768 \text{PolyLog}\left (4,e^{2 \tanh ^{-1}(a x)}\right )-256 \tanh ^{-1}(a x)^4+1024 \tanh ^{-1}(a x)^3 \log \left (1-e^{2 \tanh ^{-1}(a x)}\right )-576 \tanh ^{-1}(a x)^2 \sinh \left (2 \tanh ^{-1}(a x)\right )-24 \tanh ^{-1}(a x)^2 \sinh \left (4 \tanh ^{-1}(a x)\right )-288 \sinh \left (2 \tanh ^{-1}(a x)\right )-3 \sinh \left (4 \tanh ^{-1}(a x)\right )+384 \tanh ^{-1}(a x)^3 \cosh \left (2 \tanh ^{-1}(a x)\right )+32 \tanh ^{-1}(a x)^3 \cosh \left (4 \tanh ^{-1}(a x)\right )+576 \tanh ^{-1}(a x) \cosh \left (2 \tanh ^{-1}(a x)\right )+12 \tanh ^{-1}(a x) \cosh \left (4 \tanh ^{-1}(a x)\right )+16 \pi ^4}{1024} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 0.477, size = 1533, normalized size = 5.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (-a x + 1\right )^{4} + 2 \,{\left (2 \, a^{2} x^{2} + 2 \,{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x + 1\right ) - 3\right )} \log \left (-a x + 1\right )^{3}}{64 \,{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )}} - \frac{1}{8} \, \int \frac{4 \, \log \left (a x + 1\right )^{3} - 12 \, \log \left (a x + 1\right )^{2} \log \left (-a x + 1\right ) + 3 \,{\left (2 \, a^{4} x^{4} + 2 \, a^{3} x^{3} - 3 \, a^{2} x^{2} - 3 \, a x + 2 \,{\left (a^{6} x^{6} + a^{5} x^{5} - 2 \, a^{4} x^{4} - 2 \, a^{3} x^{3} + a^{2} x^{2} + a x + 2\right )} \log \left (a x + 1\right )\right )} \log \left (-a x + 1\right )^{2}}{4 \,{\left (a^{6} x^{7} - 3 \, a^{4} x^{5} + 3 \, a^{2} x^{3} - x\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\operatorname{artanh}\left (a x\right )^{3}}{a^{6} x^{7} - 3 \, a^{4} x^{5} + 3 \, a^{2} x^{3} - x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{\operatorname{atanh}^{3}{\left (a x \right )}}{a^{6} x^{7} - 3 a^{4} x^{5} + 3 a^{2} x^{3} - x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{\operatorname{artanh}\left (a x\right )^{3}}{{\left (a^{2} x^{2} - 1\right )}^{3} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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